7d^2+11d=0

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Solution for 7d^2+11d=0 equation:



7d^2+11d=0
a = 7; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·7·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*7}=\frac{-22}{14} =-1+4/7 $
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*7}=\frac{0}{14} =0 $

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